Added: Initial world generation tool
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// Package check holds the generator's integration tests: the ones that need more than one package and so
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// cannot live in either. There are two, and they are the two that matter.
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//
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// Determinism is a promise the project makes (cross-cutting rule 12) and Go is the language most likely to
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// break it quietly, so it is asserted rather than assumed. Steady state is the physics: if the solver does
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// not reproduce the analytic stream-power answer on a case with a known answer, every prettier result it
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// produces is a coincidence.
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package check
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import (
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"crypto/sha256"
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"encoding/hex"
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"math"
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"runtime"
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"sort"
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"testing"
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"unsafe"
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"salty/terrain/internal/coast"
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"salty/terrain/internal/fluvial"
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"salty/terrain/internal/manifest"
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"salty/terrain/internal/uplift"
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)
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func hash(v []float32) string {
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b := unsafe.Slice((*byte)(unsafe.Pointer(&v[0])), len(v)*4)
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sum := sha256.Sum256(b)
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return hex.EncodeToString(sum[:8])
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}
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// run is one whole small pipeline: uplift, the solve, then the coast. All three are in it because all three
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// are parallel, and the coast pass in particular has two places determinism could leak — the fetch rays run
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// over a slice of the waterline, and the sediment scatter accumulates several land cells into one shore cell,
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// which is why that scatter is deliberately serial.
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func run(size, steps int) []float32 {
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m := manifest.Defaults()
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m.Source.Seed = 7
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up := uplift.Build(size, 40, m)
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h := up.Height.Clone()
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g := fluvial.NewGrid(size, size, 40, up.Base)
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g.SetElevationRange(-2000, 4000)
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g.Run(h.Data, up.Rate.Data, nil, fluvial.Params{
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K: 5e-5, M: 0.5, N: 1, DtYr: 1500, Steps: steps, Diffusion: 0.02, FillEvery: 1,
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}, nil)
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coast.Build(coast.Input{
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Height: h, Sea: up.Base, SeaLevelM: m.SeaLevelM,
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BreakM: -m.Pipeline.Continent.SeaFloorM.Hi(), AbyssM: -m.Pipeline.Continent.SeaFloorM.Lo(),
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Flow: g.Area, Seed: m.Source.Seed, Cfg: m.Pipeline.Coast,
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})
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return h.Data
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}
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// TestDeterministicAcrossGOMAXPROCS is the assertion Docs/Terrain.md makes about the Go core: the result must
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// be byte-identical however many cores it ran on. Go offers three good ways to break this - randomised map
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// iteration, goroutine completion order, and a shared global RNG - so it is worth a test rather than a
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// comment.
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func TestDeterministicAcrossGOMAXPROCS(t *testing.T) {
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was := runtime.GOMAXPROCS(1)
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defer runtime.GOMAXPROCS(was)
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single := run(128, 40)
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hSingle := hash(single)
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for _, procs := range []int{2, 4, 8, 16} {
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if procs > runtime.NumCPU()*2 {
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continue
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}
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runtime.GOMAXPROCS(procs)
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got := hash(run(128, 40))
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if got != hSingle {
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t.Fatalf("GOMAXPROCS=%d gave %s, GOMAXPROCS=1 gave %s: the pipeline is not deterministic", procs, got, hSingle)
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}
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}
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}
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// TestSameSeedSameResult guards the other half of rule 12: a seed names a world.
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func TestSameSeedSameResult(t *testing.T) {
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if a, b := hash(run(96, 20)), hash(run(96, 20)); a != b {
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t.Fatalf("two runs of one seed differ: %s vs %s", a, b)
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}
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}
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// TestSteadyStateMatchesStreamPower is the physics check. On a uniform uplift field with uniform erodibility,
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// the analytic steady state of dh/dt = U - K*A^m*S^n is S = (U/K)^(1/n) * A^(-m/n), so K*A^m*S^n / U must be
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// 1 at every channel cell. Anything systematically off means the implicit update, the drainage accumulation
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// or the stack order is wrong, and no amount of tuning would fix it.
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func TestSteadyStateMatchesStreamPower(t *testing.T) {
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const (
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size = 160
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cellM = 50.0
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k = 1e-4
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mExp = 0.5
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nExp = 1.0
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u = 1e-3 // m/yr
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)
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base := make([]bool, size*size) // no ocean: the borders are the outlets
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h := make([]float32, size*size)
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rate := make([]float32, size*size)
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// A little noise so the flow network has something to organise; the answer must not depend on it.
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seed := uint32(12345)
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for i := range h {
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seed = seed*1664525 + 1013904223
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h[i] = float32(seed>>8&0xffff) / 65535 * 5
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rate[i] = u
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}
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g := fluvial.NewGrid(size, size, cellM, base)
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g.SetElevationRange(-100, 5000)
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g.Run(h, rate, nil, fluvial.Params{
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K: k, M: mExp, N: nExp, DtYr: 2000, Steps: 4000, Diffusion: 0, FillEvery: 1,
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}, nil)
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// Only well-developed channels: headwaters are hillslopes, where stream power is not the whole story
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// and where the discrete D8 grid quantises slope badly.
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var ratios []float64
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threshold := 200 * cellM * cellM
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for i := range h {
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r := g.Receiver[i]
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if int(r) == i || g.Base[i] || float64(g.Area[i]) < threshold {
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continue
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}
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s := float64(h[i]-h[r]) / float64(g.Length[i])
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if s <= 0 {
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continue
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}
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ratios = append(ratios, k*math.Pow(float64(g.Area[i]), mExp)*math.Pow(s, nExp)/u)
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}
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if len(ratios) < 100 {
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t.Fatalf("only %d channel cells; the solve did not organise a network", len(ratios))
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}
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sort.Float64s(ratios)
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median := ratios[len(ratios)/2]
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if math.Abs(median-1) > 0.1 {
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t.Errorf("median K*A^m*S^n/U = %.4f over %d channel cells, want 1.0 +/- 0.1: "+
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"the solve is not reaching the analytic steady state", median, len(ratios))
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}
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t.Logf("steady state check: median ratio %.4f over %d channel cells", median, len(ratios))
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}
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